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Give a path in Google Drive to which Google Earth Engine should export the file to

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My question is similar to this one, with the only difference that:

  1. the question in the link above is 3 years old
  2. I have one main Folder, inside that folder, I have 11 subfolders, and inside each of the 11 subfolders I have 5 subfolders. The 11 subfolders have different names but the 5 subfolders inside them they have the same name. Below you can see the structure (apologies for the bad hand writing)

main and sub

The picture above shows the main folder, called Landsat-5, and the 11 subfolders.

sub-subfolders

The picture above shows the subfolders, inside one of the subfolders.

My goal is to store different exports from Google Earth Engine (GEE) in separate subfolders on my Google Drive. I'm using Export.image.toDrive:

Export.image.toDrive({
image: export_img,
folder: export_path,
fileNamePrefix: filename,
});
Like in the question I provided in the attached link, I tried the same things and had the same results, it just creates a folder with a corresponding name in my Drive root folder.

Is there to a way to specify a path (e.g., Landsat-5/london/2015) to the Export.Image.toDrive command?


   
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Can’t install any Nvidia driver

When i run:

sudo ubuntu-drivers devices
== /sys/devices/pci0000:00/0000:00:01.0/0000:01:00.0 ==
modalias : pci:v000010DEd00002520sv00001025sd00001547bc03sc00i00
vendor   : NVIDIA Corporation  
model    : GA106M [GeForce RTX 3060 Mobile / Max-Q]  
driver   : nvidia-driver-525-open - third-party non-free recommended  
driver   : nvidia-driver-515-server - distro non-free  
driver   : nvidia-driver-510 - distro non-free  
driver   : nvidia-driver-470-server - distro non-free  
driver   : nvidia-driver-515 - distro non-free
driver   : nvidia-driver-470 - distro non-free
driver   : nvidia-driver-515-open - distro non-free
driver   : nvidia-driver-525 - third-party non-free
driver   : nvidia-driver-525-server - distro non-free
driver   : xserver-xorg-video-nouveau - distro free builtin

When i install the recommended driver (nvidia-driver-525-open), i get a black screen.

When i install nvidia-driver-515 (or any below version) i get stuck at login screen (keyboard, mouse, nothing is working… even ctrl+alt+f1 to open another tty).

This is the bug report log for the nvidia-driver-525:
https://forums.developer.nvidia.com/uploads/short-url/hu0foxXT3RfYSgvYz9Ei2dMtDdZ.log

Laptop: Acer Predator Helios 300 PH315-54-760S Gaming Laptop
GPU: NVIDIA GeForce RTX 3060
Kernel: 5.15.0-57-generic
OS: Ubuntu 22.04.2 LTS

Please help me!

Centering a string in another

I have a string of length N which I want to center in another string.

Thus setting some string of length N

old_string="***"

I want a new string (length 55) with the old string centered in it.

new_string="     ***     "

How can I do this in bash ?

Although in actual fact the trailing spaces are redundant, so I can-simply have

new_string="     ***"

What is the relationship between measurable or continuos cross-sections?

$begingroup$

Let $G$ be a locally compact Polish (or compact) group acting continuously on a locally compact Polish (or compact) space $X$, and $mu$ a Borel measure on $X$. To be sure, continuity of the action means that the map $(g, x) in G times X mapsto g cdot x in X$ is continuous with respect to the product topology on $G times X$. Let $X/G$ denote the orbit space endowed with the quotient topology, and $pi : X rightarrow X/G$ denote the orbit map. A cross-section to the orbit map is a map $s: X/G rightarrow X$ satisfying $s circ pi = 1_{X}$. If $s$ and $t$ are measurable or continuous cross-sections to the orbit map, then it is known that their images $s(X/G)$ and $t(X/G)$ are measurable (closed in the case of a continuous cross-section with compact $G$ and $X$). What is the relationship between $mu(s(X/G)$ and $mu(t(X/G))$? Is it reasonable to expect $mu(s(X/G)) = mu(t(X/G))$?

PS: It is enough for me to consider the case of $X = G$, that is, $X$ is the underlying topological space of $G$, and the action of conjugation, and $mu$ Haar measure on $G$. Thanks.

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Chromebook dying unexpectedly

My school provides me with a Chromebook.

Today, I closed the lid, then opened it up, expecting to see the lock screen, but instead, I saw where I last left off. I thought it might be because I had used the super zoom (ctrl+alt+brightness) because that usually happens, but instead of working again, it just turned off, and won’t turn back on.

It is charging but should show the low battery error, which it does not.

Find orthogonal vectors in relation to span

$begingroup$

Consider $R^3$ as an inner product space in relation to scalarmultiplication. Find all vectors in the subspace

$$Spanbigg(bigg[begin{matrix}1\2\1
end{matrix}bigg],bigg[begin{matrix}3\4\1
end{matrix}bigg]bigg)subseteq R^3,$$

which are orthogonal to the vector $bigg[begin{matrix}-1\1\1
end{matrix}bigg]$

Any help will be appreciated. I tried finding the random vector $v=bigg[begin{matrix}x_1\x_2\x_3
end{matrix}bigg]$
in the plane which i found to be ${x_3cdotbigg[begin{matrix}1\-1\1
end{matrix}bigg]bigg}$
but i dont know where to go from here.

$endgroup$

I derived a formula for [x!]’ is it correct?

$begingroup$

The starting point was that $ Gamma'(x+1)=Gamma(x+1)psi(x+1)$ where $psi(x+1)=-gamma+H_{x}$ . Hence $$ [x!]’ = x!biggl[-gamma+sum_{k=1}^{x}frac{1}{k}biggl]$$ For example $ [4!]’ = 24[-gamma+1+1/2+1/3+1/4]$ which gives 36.1462 that, put in the tangent equation, gives us exactly the tangent for x=4! Let me know if I made any mistakes in the derivation/generalization!

$endgroup$

An inequality about the 2-Wasserstein distance

$begingroup$

Let $W_2(mu,nu)$ denote the $2$-Wasserstein distance between two given probability measures $mu$ and $nu$ on $mathbb R^n$. For a probability measure $mu$ and $f:mathbb R^nto mathbb R^n$, let $f_{#}mu=mucirc f^{-1}$ denote the push-forward of $mu$ under $f$, i.e. $(f_{#}mu)(B)=mu(f^{-1}(B))$ for every Borel set $B$ in $mathbb R^n$. Why does the following inequality hold true?
$$W^2_2(f_{#}mu,g_{#}mu)leq int_{mathbb R^n}|f(x)-g(x)|^2,dmu(x) $$
for all $mu$-measurable functions $f,g:mathbb R^ntomathbb R^n$.

Some comment: the product measure $f_{#}muotimes g_{#}mu$ is a so-called transport plan and by definition of the Wasserstein distance
$$W^2_2(f_{#}mu,g_{#}mu)leq int_{mathbb R^ntimes mathbb R^n}|x-y|^2,d(f_{#}muotimes g_{#}mu)(x,y)=int_{mathbb R^ntimes mathbb R^n}|f(x)-g(y)|^2,dmu(x),dmu(y).$$

$endgroup$

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